MCQOPTIONS
Saved Bookmarks
| 1. |
What is the equation used to find the PSI in rigid pavements? |
| A. | <em>PSI=5.03-0.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} ) |
| B. | <em>PSI=5.41-0.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} ) |
| C. | <em>PSI=5.03-1.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} ) |
| D. | <em>PSI=5.41-1.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} ) |
| Answer» E. | |