1.

What is the equation used to find the PSI in rigid pavements?

A. <em>PSI=5.03-0.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} )
B. <em>PSI=5.41-0.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} )
C. <em>PSI=5.03-1.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} )
D. <em>PSI=5.41-1.80 log u2061(1+SV)-0.09</em> ( sqrt{C+P} )
Answer» E.


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