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| 1. |
What is the equation used to find the PSI for flexible pavements? |
| A. | <em>PSI=5.03-1.91 log u2061(1+SV)-1.38(RD)<sup>3</sup>-0.01</em> ( sqrt{C+P} ) |
| B. | <em>PSI=5.41-1.91 log u2061(1+SV)-1.38(RD)<sup>2</sup>-0.01</em> ( sqrt{C+P} ) |
| C. | <em>PSI=5.03-1.91 log u2061(1+SV)-1.38(RD)<sup>2</sup>-0.01</em> ( sqrt{C+P} ) |
| D. | <em>PSI=5.41-1.91 log u2061(1+SV)-1.38(RD)<sup>3</sup>-0.01</em> ( sqrt{C+P} ) |
| Answer» D. <em>PSI=5.41-1.91 log u2061(1+SV)-1.38(RD)<sup>3</sup>-0.01</em> ( sqrt{C+P} ) | |