What is the equation used to find the PSI in rigid pavements?

• A. PSI=5.03-0.80 log⁡(1+SV)-0.09\(\sqrt{C+P}\)
• B. PSI=5.41-0.80 log⁡(1+SV)-0.09\(\sqrt{C+P}\)
• C. PSI=5.03-1.80 log⁡(1+SV)-0.09\(\sqrt{C+P}\)
• D. PSI=5.41-1.80 log⁡(1+SV)-0.09\(\sqrt{C+P}\)