MCQOPTIONS
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MCQOPTIONS
| 1. |
What is the equation used to find the PSI for flexible pavements? |
| A. | PSI=5.03-1.91 log(1+SV)-1.38(RD)3-0.01\(\sqrt{C+P}\) |
| B. | PSI=5.41-1.91 log(1+SV)-1.38(RD)2-0.01\(\sqrt{C+P}\) |
| C. | PSI=5.03-1.91 log(1+SV)-1.38(RD)2-0.01\(\sqrt{C+P}\) |
| D. | PSI=5.41-1.91 log(1+SV)-1.38(RD)3-0.01\(\sqrt{C+P}\) |
| Answer» D. PSI=5.41-1.91 log(1+SV)-1.38(RD)3-0.01\(\sqrt{C+P}\) | |