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| 1. |
The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.Find the value of energy at the point where the interatomic force is zero? |
| A. | – ε |
| B. | ε |
| C. | 0 |
| D. | σ |
| Answer» B. ε | |