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				| 1. | The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.Find the value of energy at the point where the interatomic force is zero? | 
| A. | – ε | 
| B. | ε | 
| C. | 0 | 
| D. | σ | 
| Answer» B. ε | |