The following equation gives the variation of interatomic energy with atomic distance:V(r)=4ε[(σ/r12)−(σ/r6)] Where V(r) is the potential energy and r is interatomic distance. ε and σ are constant.Find the value of interatomic distance where energy is minimum?

The following equation gives the variation of interatomic energy with

1.	The following equation gives the variation of interatomic energy with atomic distance:V(r)=4ε[(σ/r12)−(σ/r6)] Where V(r) is the potential energy and r is interatomic distance. ε and σ are constant.Find the value of interatomic distance where energy is minimum?
A.	0
B.	ε
C.	σ
D.	1.2 σ
Answer» E.

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The following equation gives the variation of interatomic energy with atomic distance:V(r)=4ε[(σ/r12)−(σ/r6)] Where V(r) is the potential energy and r is interatomic distance. ε and σ are constant.Find the value of interatomic distance where energy is minimum?

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