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The polar plot in the given figure is for the term
1.
The polar plot in the given figure is for the term
A.
jωT
B.
1 + jωT
Answer» C.
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N circles for a = a1, and a = a1 ± 180° n (where n = 1, 2, 3, ....) are the same.
Nichol's chart is symmetric about - 180° axis.
At low frequencies the factor e-jωT and behave simple.
For type 0 system the starting point (i.e. ω = 0) of polar plot is finite and is on positive real axis.
For as ω approaches infinity, the magnitude approaches zero and phase angle approaches - 90°.
The phase angle curve of G(jω) H(jω) is drawn by adding the phase angles of individual factors.
At corner frequency the phase angle of factor is - 45°
The phase angle of is constant and equal to - 90° for all values of ω
The log magnitude curve of factor jω is a straight line having a slope of 20 dB/decade.
Transfer functions of even complicated components can be found by frequency response tests.
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