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1. |
The current equation obtained from the circuit shown below is? |
A. | i=e-200t (1.04 sin979.8t)A |
B. | i=e-200t (2.04 sin979.8t)A |
C. | i=e-200t (3.04 sin979.8t)A |
D. | i=e-200t (4.04 sin979.8t)A |
Answer» C. i=e-200t (3.04 sin979.8t)A | |