The circuit shown in the figure consists of resistance, capacitance and inductance in series with a 100V source when the switch is closed at t = 0. Find the equation obtained from the circuit in terms of current.

• A. 100 = 20i + 0.05 \(\frac{di}{dt} + \frac{1}{20 \times 10^{-6}} \int idt\)
• B. 100 = 20i – 0.05 \(\frac{di}{dt} + \frac{1}{20 \times 10^{-6}} \int idt\)
• C. 100 = 20i + 0.05 \(\frac{di}{dt} – \frac{1}{20 \times 10^{-6}} \int idt\)
• D. 100 = 20i – 0.05 \(\frac{di}{dt} – \frac{1}{20 \times 10^{-6}} \int idt\)