The centre of gravity of the trapezium as shown in below figure from – McqOptions

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1.	The centre of gravity of the trapezium as shown in below figure from the side is at a distance of
A.	(h/3) × [(b + 2a)/(b + a)]
B.	(h/3) × [(2b + a)/(b + a)]
C.	(h/2) × [(b + 2a)/(b + a)]
D.	(h/2) × [(2b + a)/(b + a)]
Answer» B. (h/3) × [(2b + a)/(b + a)]

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