Maximum principal moment of inertia is

1.	Maximum principal moment of inertia is
A.	the position of an area along which it can resist maximum force
B.	the position of an area along which it can resist maximum torque
C.	the position of an area along which it can resist maximum bending moment
D.	the position of an area along which it can resist maximum shear
Answer» D. the position of an area along which it can resist maximum shear

Discussion

No Comment Found

Related MCQs

A slab is subjected to two forces F1 and F2 of same magnitude as shown in the figure. Force F2 is in xy-plane while force F1 acts along Z-axis at the point \(\left( {2\hat i + 3\hat j} \right).\) The moment of these forces about point O will be
Particle undergoes uniform circular motion. About which point on the plane of the circle, the angular momentum of the particle will remains conserved?
A solid sphere & a hollow sphere of radius R are rolling down in inclined lane of height h. The ratio of velocities of solid sphere to Hollow sphere on reaching the bottom is
If a disc has moment of inertia I about the axis which is tangential and in plane of the disc, then the moment of inertia about the axis which is tangential and perpendicular to its plane will be:
If the radius of earth is 6400 km. then angular velocity for a point on its equator will be -
A uniform rectangular thin sheet ABCD of mass M has length ‘a’ and breadth ‘b’, as shown in the figure. If the shaded portion HBGO is cut-off, the coordinates of the centre of mass of the remaining portion will be:
Moment of inertia of a thin circular ring of mass M and R rotating about an axis, passing through its centre and perpendicular to the plane is
Charge is distributed within a sphere of radius R with a volume charge density \(\rho \left( r \right) = \frac{{\rm{A}}}{{{{\rm{r}}^2}}}{{\rm{e}}^{ - 2{\rm{r}}/{\rm{a}}}}\), where A and a are constants. If Q is the total charge of this charge distribution, the radius R is:
A circular disc of radius b has a hole of radius ‘a’ at its centre (see figure). If the mass per unit area of the disc varies as \(\left( {\frac{{{\sigma _0}}}{{\rm{r}}}} \right)\), then the radius of gyration of the disc about its axis passing through the centre is:
In an experiment, electrons are accelerated, from rest by applying a voltage of 500 V. Calculate the radius of the path, if a magnetic field 100 mT is then applied.(Take, charge of the electron = 1.6 × 10-19 C and mass of the electron = 9.1 × 10-31 kg)

Maximum principal moment of inertia is

Discussion

No Comment Found

Related MCQs

Reply to Comment