\(\mathop {{\rm{lim}}}\limits_{x \to \infty } \left( {\frac{{2 + {x^2}}}{{1 + x\;}} - Ax - B} \right) = 3\)What is the value of B?

\(\mathop {{\rm{lim}}}\limits_{x \to \infty } \left( {\frac{{2 + {x^2}

1.	\(\mathop {{\rm{lim}}}\limits_{x \to \infty } \left( {\frac{{2 + {x^2}}}{{1 + x\;}} - Ax - B} \right) = 3\)What is the value of B?
A.	-4
B.	1
C.	2
D.	3
Answer» B. 1

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\(\mathop {{\rm{lim}}}\limits_{x \to \infty } \left( {\frac{{2 + {x^2}}}{{1 + x\;}} - Ax - B} \right) = 3\)What is the value of B?

\(\mathop {{\rm{lim}}}\limits_{x \to \infty } \left( {\frac{{2 + {x^2}}}{{1 + x\;}} - Ax - B} \right) = 3\)What is the value of B?

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