If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{{\rm{sin}}\left( {{{\rm{e}}^{{\rm{x}} - 2}} - 1} \right)}}{{{\rm{In}}\left( {{\rm{x}} - 1} \right)}}\), then \(\mathop {\lim }\limits_{{\rm{x}} \to 2} {\rm{f}}\left( {\rm{x}} \right)\) is equal to

If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{{\rm{sin}}\left( {{{\rm{

1.	If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{{\rm{sin}}\left( {{{\rm{e}}^{{\rm{x}} - 2}} - 1} \right)}}{{{\rm{In}}\left( {{\rm{x}} - 1} \right)}}\), then \(\mathop {\lim }\limits_{{\rm{x}} \to 2} {\rm{f}}\left( {\rm{x}} \right)\) is equal to
A.	-2
B.	-1
C.	0
D.	1
Answer» E.

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If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{{\rm{sin}}\left( {{{\rm{e}}^{{\rm{x}} - 2}} - 1} \right)}}{{{\rm{In}}\left( {{\rm{x}} - 1} \right)}}\), then \(\mathop {\lim }\limits_{{\rm{x}} \to 2} {\rm{f}}\left( {\rm{x}} \right)\) is equal to

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