If \({\rm{G}}\left( {\rm{x}} \right) = \sqrt {(25 - {{\rm{x}}^2}} \) then what is \(\mathop {\lim }\limits_{{\rm{x}} \to 1} \frac{{{\rm{G}}\left( {\rm{x}} \right) - {\rm{G}}\left( 1 \right)}}{{{\rm{x}} - 1}}{\rm{\;}}\)equal to?

\(- \frac{1}{{2\sqrt 6 {\rm{\;\;}}}}\)

If \({\rm{G}}\left( {\rm{x}} \right) = \sqrt {(25 - {{\rm{x}}^2}} \)

1.	If \({\rm{G}}\left( {\rm{x}} \right) = \sqrt {(25 - {{\rm{x}}^2}} \) then what is \(\mathop {\lim }\limits_{{\rm{x}} \to 1} \frac{{{\rm{G}}\left( {\rm{x}} \right) - {\rm{G}}\left( 1 \right)}}{{{\rm{x}} - 1}}{\rm{\;}}\)equal to?
A.	\(- \frac{1}{{2\sqrt 6 {\rm{\;\;}}}}\)
B.	\(\frac{1}{5}\)
C.	\(- \frac{1}{{\sqrt 6 }}\)
D.	\(\frac{1}{{\sqrt 6 }}\)
Answer» B. \(\frac{1}{5}\)

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If \({\rm{G}}\left( {\rm{x}} \right) = \sqrt {(25 - {{\rm{x}}^2}} \) then what is \(\mathop {\lim }\limits_{{\rm{x}} \to 1} \frac{{{\rm{G}}\left( {\rm{x}} \right) - {\rm{G}}\left( 1 \right)}}{{{\rm{x}} - 1}}{\rm{\;}}\)equal to?

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