\(\displaystyle\lim_{x\rightarrow 0} \dfrac{a^x-b^x}{e^x-1}\) is equa

1.	\(\displaystyle\lim_{x\rightarrow 0} \dfrac{a^x-b^x}{e^x-1}\) is equal to :
A.	\(\log \left(\dfrac{a}{b}\right)\)
B.	\(\log \left(\dfrac{b}{a}\right)\)
C.	log (a, b)
D.	log (a + b)
Answer» B. \(\log \left(\dfrac{b}{a}\right)\)

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