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| 1. |
Let A(3, 0, -1), B(2, 10, 6) and C(1, 2, 1) be the vertices of a triangle and M be the midpoint of AC. If G divides BM in the ratio, 2:1, then cos (∠GOA) (O being the origin) is equal to: |
| A. | \(\frac{1}{{2\sqrt {15} }}\) |
| B. | \(\frac{1}{{\sqrt {15} }}\) |
| C. | \(\frac{1}{{6\sqrt {10} }}\) |
| D. | \(\frac{1}{{\sqrt {30} }}\) |
| Answer» C. \(\frac{1}{{6\sqrt {10} }}\) | |