Let \(0 < {\rm{\theta }} < \frac{{\rm{\pi }}}{2}\). If the eccentricity of the hyperbola \(\frac{{{{\rm{x}}^2}}}{{{\rm{co}}{{\rm{s}}^2}{\rm{\theta }}}} - \frac{{{{\rm{y}}^2}}}{{{\rm{si}}{{\rm{n}}^2}{\rm{\theta }}}} = 1\) is greater than 2, then the length of its latus rectum lies in the interval:

\(\left( {\frac{3}{2},{\rm{\;}}2} \right]\)

\(\left( {1,{\rm{\;}}\frac{3}{2}} \right]\)

Let \(0 < {\rm{\theta }} < \frac{{\rm{\pi }}}{2}\). If the eccentrici

1.	Let \(0 < {\rm{\theta }} < \frac{{\rm{\pi }}}{2}\). If the eccentricity of the hyperbola \(\frac{{{{\rm{x}}^2}}}{{{\rm{co}}{{\rm{s}}^2}{\rm{\theta }}}} - \frac{{{{\rm{y}}^2}}}{{{\rm{si}}{{\rm{n}}^2}{\rm{\theta }}}} = 1\) is greater than 2, then the length of its latus rectum lies in the interval:
A.	(3, ∞)
B.	\(\left( {\frac{3}{2},{\rm{\;}}2} \right]\)
C.	(2, 3]
D.	\(\left( {1,{\rm{\;}}\frac{3}{2}} \right]\)
Answer» B. \(\left( {\frac{3}{2},{\rm{\;}}2} \right]\)

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Let \(0 < {\rm{\theta }} < \frac{{\rm{\pi }}}{2}\). If the eccentricity of the hyperbola \(\frac{{{{\rm{x}}^2}}}{{{\rm{co}}{{\rm{s}}^2}{\rm{\theta }}}} - \frac{{{{\rm{y}}^2}}}{{{\rm{si}}{{\rm{n}}^2}{\rm{\theta }}}} = 1\) is greater than 2, then the length of its latus rectum lies in the interval:

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