If the foci of the ellipse \(b^2x^2 +16y^2 = 16b^2\) and the hyperbola \(81x^2 -144y^2 = \dfrac{81 \times 144}{25}\) coincide, then the value of b, is

If the foci of the ellipse \(b^2x^2 +16y^2 = 16b^2\) and the hyperbo

1.	If the foci of the ellipse \(b^2x^2 +16y^2 = 16b^2\) and the hyperbola \(81x^2 -144y^2 = \dfrac{81 \times 144}{25}\) coincide, then the value of b, is
A.	1
B.	\(\sqrt{5}\)
C.	\(\sqrt{7}\)
D.	3
Answer» D. 3

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If the foci of the ellipse \(b^2x^2 +16y^2 = 16b^2\) and the hyperbola \(81x^2 -144y^2 = \dfrac{81 \times 144}{25}\) coincide, then the value of b, is

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