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1. |
If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x - a2) = 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of ‘a’ is: |
A. | \(5\sqrt 5 \) |
B. | 5(21⁄3) |
C. | 102⁄3 |
D. | 5 |
Answer» E. | |