1.

If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x - a2) = 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of ‘a’ is:

A. \(5\sqrt 5 \)
B. 5(21⁄3)
C. 102⁄3
D. 5
Answer» E.


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