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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.
1. |
Directions: The temperature of a liquid can be measured in kelvin units as\[\mathbf{x{}^\circ K}\] or in Fahrenheit units Units as\[\mathbf{y{}^\circ F}\], the relation between the two system of measurement of temperature is given by the linear equation\[\mathbf{y-32=}\frac{\mathbf{9}}{\mathbf{2}}\mathbf{(x-273)}\]. Based on this information, answer the following questions: Find the temperature of the liquid in Fahrenheit if the temperature of the liquid is \[\mathbf{333{}^\circ K}\] |
A. | \[-\,140{}^\circ F\] |
B. | \[140{}^\circ F\] |
C. | \[158{}^\circ F\] |
D. | \[-\,158{}^\circ F\] |
E. | None of these |
Answer» C. \[158{}^\circ F\] | |
2. |
\[{{\mathbf{(}\sqrt{\mathbf{P}}\mathbf{-}\sqrt{\mathbf{Q}}\mathbf{)}}^{\mathbf{3}}}\mathbf{+(}\sqrt{\mathbf{Q}}\mathbf{-}\sqrt{\mathbf{R}}{{\mathbf{)}}^{\mathbf{3}}}\mathbf{+(}\sqrt{\mathbf{R}}\mathbf{-}\sqrt{\mathbf{P}}{{\mathbf{)}}^{\mathbf{3}}}\] equals to _______ |
A. | \[3(P-Q)(Q-R)(R-P)\] |
B. | \[3(\sqrt{P}-\sqrt{Q})(\sqrt{Q}-\sqrt{R})(\sqrt{R}-\sqrt{P})\] |
C. | \[\sqrt{3}(\sqrt{P}-\sqrt{Q})(\sqrt{Q}-\sqrt{R})(\sqrt{R}-\sqrt{P})\] |
D. | All the above |
E. | None of these |
Answer» C. \[\sqrt{3}(\sqrt{P}-\sqrt{Q})(\sqrt{Q}-\sqrt{R})(\sqrt{R}-\sqrt{P})\] | |
3. |
\[\mathbf{x=-5}\] and \[\mathbf{y=1}\] is a solution of the linear equation _______ |
A. | \[x-2y= 7\] |
B. | \[3y-x=-\,8\] |
C. | \[6y-x=11\] |
D. | \[3x=15y\] |
E. | None of these |
Answer» D. \[3x=15y\] | |
4. |
The area of a square whose opposite vertices are \[\mathbf{(0, 0)}\]and \[\mathbf{(6,6)}\]is _______ |
A. | \[36\text{ }unit{{s}^{2}}\] |
B. | \[30\text{ }unit{{s}^{2}}\] |
C. | \[34\text{ }unit{{s}^{2}}\] |
D. | Cannot be determined |
E. | None of these |
Answer» B. \[30\text{ }unit{{s}^{2}}\] | |
5. |
\[{{\mathbf{l}}^{\mathbf{3}}}{{\mathbf{(m-n)}}^{\mathbf{3}}}\mathbf{+}{{\mathbf{m}}^{\mathbf{3}}}{{\mathbf{(n-l)}}^{\mathbf{3}}}\mathbf{+}{{\mathbf{n}}^{\mathbf{3}}}{{\mathbf{(l-m)}}^{\mathbf{3}}}\]equals to _________ |
A. | \[{{(lmn)}^{3}}(l-m)(m-n)(n-l)\] |
B. | \[(lm+mn+nl)(3{{l}^{2}}{{m}^{2}}{{n}^{2}})\] |
C. | \[3lmn(m-n)(n-l)(l-m)\] |
D. | 0 |
E. | None of these |
Answer» D. 0 | |