In the given figure, O is the center of the circle, OQ is perpendicular to RS and ∠SRT = 30°. If RS = 10√2, then what is the of PR2?

In the given figure, O is the center of the circle, OQ is perpendicula

1.	In the given figure, O is the center of the circle, OQ is perpendicular to RS and ∠SRT = 30°. If RS = 10√2, then what is the of PR2?
A.	200 (1 + √3)
B.	300 (2 + √3)
C.	200 (2 + √3)
D.	100 (3 + 2√3)
Answer» D. 100 (3 + 2√3)

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In the given figure, O is the center of the circle, OQ is perpendicular to RS and ∠SRT = 30°. If RS = 10√2, then what is the of PR2?

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