In ΔABC, P is a point on BC such the BP : PC = 4 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : Ar(ΔABC) is equal to:

In ΔABC, P is a point on BC such the BP : PC = 4 : 3 and Q is the mid

1.	In ΔABC, P is a point on BC such the BP : PC = 4 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : Ar(ΔABC) is equal to:
A.	1 : 5
B.	4 : 7
C.	2 : 7
D.	3 : 7
Answer» D. 3 : 7

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In ΔABC, P is a point on BC such the BP : PC = 4 : 3 and Q is the midpoint of BP. Then ar(ΔABQ) : Ar(ΔABC) is equal to:

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