In ΔABC, ∠C = 90°, Point P and Q are on the sides AC and BC, respectively, such that AP : PC = BQ : QC = 1 : 2 then, \(\frac{AQ^2+BP^2}{AB^2}\) is equal to:

In ΔABC, ∠C = 90°, Point P and Q are on the sides AC and BC, res

1.	In ΔABC, ∠C = 90°, Point P and Q are on the sides AC and BC, respectively, such that AP : PC = BQ : QC = 1 : 2 then, \(\frac{AQ^2+BP^2}{AB^2}\) is equal to:
A.	4/9
B.	8/3
C.	4/3
D.	13/9
Answer» E.

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In ΔABC, ∠C = 90°, Point P and Q are on the sides AC and BC, respectively, such that AP : PC = BQ : QC = 1 : 2 then, \(\frac{AQ^2+BP^2}{AB^2}\) is equal to:

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