In ΔABC, AB = AC and AL is perpendicular to BC at L. In ΔDEF, DE = DF and DM is perpendicular to EF at M. If (area of ΔABC) : (are of ΔDEF) = 9 : 25 and ∠BAC = ∠EDF, then \(\frac{{DM\; + \;AL}}{{DM - AL}}\) is equal to:

In ΔABC, AB = AC and AL is perpendicular to BC at L. In ΔDEF, DE = D

1.	In ΔABC, AB = AC and AL is perpendicular to BC at L. In ΔDEF, DE = DF and DM is perpendicular to EF at M. If (area of ΔABC) : (are of ΔDEF) = 9 : 25 and ∠BAC = ∠EDF, then \(\frac{{DM\; + \;AL}}{{DM - AL}}\) is equal to:
A.	3
B.	5
C.	6
D.	4
Answer» E.

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In ΔABC, AB = AC and AL is perpendicular to BC at L. In ΔDEF, DE = DF and DM is perpendicular to EF at M. If (area of ΔABC) : (are of ΔDEF) = 9 : 25 and ∠BAC = ∠EDF, then \(\frac{{DM\; + \;AL}}{{DM - AL}}\) is equal to:

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