In a ΔABC, ∠A = 90°, if BM and CN are two medians, \(\frac{{B{M^2} + C{N^2}}}{{B{C^2}}}\) is equal to:

In a ΔABC, ∠A = 90°, if BM and CN are two medians, \(\frac{{B{M^

1.	In a ΔABC, ∠A = 90°, if BM and CN are two medians, \(\frac{{B{M^2} + C{N^2}}}{{B{C^2}}}\) is equal to:
A.	\(\frac{5}{4}\)
B.	\(\frac{3}{5}\)
C.	\(\frac{3}{4}\)
D.	\(\frac{4}{5}\)
Answer» B. \(\frac{3}{5}\)

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In a ΔABC, ∠A = 90°, if BM and CN are two medians, \(\frac{{B{M^2} + C{N^2}}}{{B{C^2}}}\) is equal to:

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