MCQOPTIONS
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| 1. |
If y = sin (ln x), then which one of the following is correct? |
| A. | \(\frac{{{d^2}y}}{{d{x^2}}} + y = 0\) |
| B. | \(\frac{{{d^2}y}}{{d{x^2}}} = 0\) |
| C. | \({x^2}\frac{{{d^2}y}}{{d{x^2}}} + x\frac{{dy}}{{dx}} + y = 0\) |
| D. | \({x^2}\frac{{{d^2}y}}{{d{x^2}}} - x\frac{{dy}}{{dx}} + y = 0\) |
| Answer» D. \({x^2}\frac{{{d^2}y}}{{d{x^2}}} - x\frac{{dy}}{{dx}} + y = 0\) | |