If the functionf : R - {1,-1} →Adefined by \(f\left( x \right) = \frac{{{x^2}}}{{1 - {x^2}}},{\rm{\;}}\) is surjective, then A is equal to:

If the functionf : R - {1,-1} →Adefined by \(f\left( x \right) = \f

1.	If the functionf : R - {1,-1} →Adefined by \(f\left( x \right) = \frac{{{x^2}}}{{1 - {x^2}}},{\rm{\;}}\) is surjective, then A is equal to:
A.	R - {-1}
B.	[0, ∞)
C.	R - [-1, 0)
D.	R - (-1, 0)
Answer» D. R - (-1, 0)

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If the functionf : R - {1,-1} →Adefined by \(f\left( x \right) = \frac{{{x^2}}}{{1 - {x^2}}},{\rm{\;}}\) is surjective, then A is equal to:

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