If the function f given byf(x) = x3 – 3(a – 2) x2 + 3ax + 7 for some a ∈ R is increasing in (0, 1] and decreasing in [1, 5), then a root of the equation, \(\frac{{{\rm{f}}\left( {\rm{x}} \right) - 14}}{{{{({\rm{x}} - 1)}^2}}} = 0\left( {{\rm{x}} \ne 1} \right)\)is

If the function f given byf(x) = x3 – 3(a – 2) x2 + 3ax + 7 for so

1.	If the function f given byf(x) = x3 – 3(a – 2) x2 + 3ax + 7 for some a ∈ R is increasing in (0, 1] and decreasing in [1, 5), then a root of the equation, \(\frac{{{\rm{f}}\left( {\rm{x}} \right) - 14}}{{{{({\rm{x}} - 1)}^2}}} = 0\left( {{\rm{x}} \ne 1} \right)\)is
A.	-7
B.	6
C.	7
D.	5
Answer» D. 5

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