If \(f\left( x \right) = \frac{{x - 2}}{{x + 2}},\;x \ne - 2\), then what is f-1(x) equal to?

\(\frac{{4\left( {x + 2} \right)}}{{x - 2}}\)

\(\frac{{x + 2}}{{4\left( {x - 2} \right)}}\)

\(\frac{{2\left( {1 + x} \right)}}{{1 - x}}\)

If \(f\left( x \right) = \frac{{x - 2}}{{x + 2}},\;x \ne - 2\), then w

1.	If \(f\left( x \right) = \frac{{x - 2}}{{x + 2}},\;x \ne - 2\), then what is f-1(x) equal to?
A.	\(\frac{{4\left( {x + 2} \right)}}{{x - 2}}\)
B.	\(\frac{{x + 2}}{{4\left( {x - 2} \right)}}\)
C.	\(\frac{{x + 2}}{{x - 2}}\)
D.	\(\frac{{2\left( {1 + x} \right)}}{{1 - x}}\)
Answer» E.

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