If \({\rm{f}}\left( {\rm{x}} \right) = \sqrt {25 - {{\rm{x}}^2}} {\rm{\;}},{\rm{\;}}\) then what is \(\mathop {{\rm{Lim}}}\limits_{{\rm{x}} \to 1} \frac{{{\rm{f}}\left( {\rm{x}} \right) - {\rm{f}}\left( 1 \right)}}{{{\rm{x}} - 1}}\) equal to?

If \({\rm{f}}\left( {\rm{x}} \right) = \sqrt {25 - {{\rm{x}}^2}} {\rm{

1.	If \({\rm{f}}\left( {\rm{x}} \right) = \sqrt {25 - {{\rm{x}}^2}} {\rm{\;}},{\rm{\;}}\) then what is \(\mathop {{\rm{Lim}}}\limits_{{\rm{x}} \to 1} \frac{{{\rm{f}}\left( {\rm{x}} \right) - {\rm{f}}\left( 1 \right)}}{{{\rm{x}} - 1}}\) equal to?
A.	\(\frac{1}{5}\)
B.	\(\frac{1}{24}\)
C.	\(\sqrt {24} \)
D.	\(- \frac{1}{{\sqrt {24} }}\)
Answer» E.

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If \({\rm{f}}\left( {\rm{x}} \right) = \sqrt {25 - {{\rm{x}}^2}} {\rm{\;}},{\rm{\;}}\) then what is \(\mathop {{\rm{Lim}}}\limits_{{\rm{x}} \to 1} \frac{{{\rm{f}}\left( {\rm{x}} \right) - {\rm{f}}\left( 1 \right)}}{{{\rm{x}} - 1}}\) equal to?

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