If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{\rm{x}}}{{{\rm{x}} - 1}},\) then what is \(\frac{{{\rm{f}}\left( {\rm{a}} \right)}}{{{\rm{f}}\left( {{\rm{a}} + 1} \right)}}\) equal to?

\({\rm{f}}\left( {\frac{1}{{\rm{a}}}} \right)\)

\({\rm{f}}\left( { - \frac{{\rm{a}}}{{{\rm{a}} + 1}}} \right)\)

\({\rm{f}}\left( {{{\rm{a}}^2}} \right)\)

If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{\rm{x}}}{{{\rm{x}} - 1}}

1.	If \({\rm{f}}\left( {\rm{x}} \right) = \frac{{\rm{x}}}{{{\rm{x}} - 1}},\) then what is \(\frac{{{\rm{f}}\left( {\rm{a}} \right)}}{{{\rm{f}}\left( {{\rm{a}} + 1} \right)}}\) equal to?
A.	\({\rm{f}}\left( { - \frac{{\rm{a}}}{{{\rm{a}} + 1}}} \right)\)
B.	\({\rm{f}}\left( {{{\rm{a}}^2}} \right)\)
C.	\({\rm{f}}\left( {\frac{1}{{\rm{a}}}} \right)\)
D.	f(-a)
Answer» C. \({\rm{f}}\left( {\frac{1}{{\rm{a}}}} \right)\)

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