If νt is the turbulent kinematic viscosity, lm is the mixing length and U is the mean flow velocity in the x-direction, which of these gives the Prandtl mixing length model equation?

Question

TuteeHUB · Accepted Answer

$ν_t =l_m \Big|\frac{∂U}{∂y}\Big|$

TuteeHUB · Answer

$ν_t =l_m^2 \Big|\frac{∂U}{∂x}\Big|$

TuteeHUB · Answer

$ν_t =l_m^2 \Big|\frac{∂U}{∂y}\Big|$

TuteeHUB · Answer

$ν_t =l_m \Big|\frac{∂U}{∂y}\Big|$

TuteeHUB · Answer

$ν_t =l_m^2 \Big|\frac{∂U}{∂x}\Big|$

1.	If νt is the turbulent kinematic viscosity, lm is the mixing length and U is the mean flow velocity in the x-direction, which of these gives the Prandtl mixing length model equation?
A.	\(ν_t =l_m^2 \Big\|\frac{∂U}{∂x}\Big\|\)
B.	\(ν_t =l_m^2 \Big\|\frac{∂U}{∂y}\Big\|\)
C.	\(ν_t =l_m \Big\|\frac{∂U}{∂y}\Big\|\)
D.	\(ν_t =l_m^2 \Big\|\frac{∂U}{∂x}\Big\|\)
Answer» C. \(ν_t =l_m \Big\|\frac{∂U}{∂y}\Big\|\)

If νt is the turbulent kinematic viscosity, lm is the mixing length and U is the mean flow velocity in the x-direction, which of these gives the Prandtl mixing length model equation?

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