If m is the minimum value of k for which the function $f\left( x \right)=x\sqrt{kx-{{x}^{2}}}$ is increasing in the interval [0, 3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to:

Question

If m is the minimum value of k for which the function $f\left( x \right)=x\sqrt{kx-{{x}^{2}}}$ is increasing in the interval [0, 3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to:

TuteeHUB · Accepted Answer

$\left( 3,\text{ }\!\!~\!\!\text{ }3\sqrt{3} \right)$

TuteeHUB · Answer

$\left( 4,\text{ }\!\!~\!\!\text{ }3\sqrt{2} \right)$

TuteeHUB · Answer

$\left( 4,\text{ }\!\!~\!\!\text{ }3\sqrt{3} \right)$

TuteeHUB · Answer

$\left( 5,\text{ }\!\!~\!\!\text{ }3\sqrt{6} \right)$

1.	If m is the minimum value of k for which the function \(f\left( x \right)=x\sqrt{kx-{{x}^{2}}}\) is increasing in the interval [0, 3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to:
A.	\(\left( 4,\text{ }\!\!~\!\!\text{ }3\sqrt{2} \right)\)
B.	\(\left( 4,\text{ }\!\!~\!\!\text{ }3\sqrt{3} \right)\)
C.	\(\left( 3,\text{ }\!\!~\!\!\text{ }3\sqrt{3} \right)\)
D.	\(\left( 5,\text{ }\!\!~\!\!\text{ }3\sqrt{6} \right)\)
Answer» C. \(\left( 3,\text{ }\!\!~\!\!\text{ }3\sqrt{3} \right)\)

If m is the minimum value of k for which the function \(f\left( x \right)=x\sqrt{kx-{{x}^{2}}}\) is increasing in the interval [0, 3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to:

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