MCQOPTIONS
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| 1. |
If \(f(x) = {\sin ^{ - 1}}\left[ {\frac{{\sqrt 3 }}{2}x - \frac{1}{2}\sqrt {1 - {x^2}} } \right]\), \(x \in \left[ { - \frac{1}{2},1} \right]\), then f(x) will be |
| A. | \({\sin ^{ - 1}}\left( {x - \frac{\pi }{2}} \right)\) |
| B. | \({\sin ^{ - 1}}\left( {x - \frac{\pi }{3}} \right)\) |
| C. | \({\sin ^{ - 1}}x ~-\frac{\pi}{6}\) |
| D. | \({\sin ^{ - 1}}\left( {x - \frac{\pi }{4}} \right)\) |
| Answer» D. \({\sin ^{ - 1}}\left( {x - \frac{\pi }{4}} \right)\) | |