1.

If \(f(x) = {\sin ^{ - 1}}\left[ {\frac{{\sqrt 3 }}{2}x - \frac{1}{2}\sqrt {1 - {x^2}} } \right]\), \(x \in \left[ { - \frac{1}{2},1} \right]\), then f(x) will be

A. \({\sin ^{ - 1}}\left( {x - \frac{\pi }{2}} \right)\)
B. \({\sin ^{ - 1}}\left( {x - \frac{\pi }{3}} \right)\)
C. \({\sin ^{ - 1}}x ~-\frac{\pi}{6}\)
D. \({\sin ^{ - 1}}\left( {x - \frac{\pi }{4}} \right)\)
Answer» D. \({\sin ^{ - 1}}\left( {x - \frac{\pi }{4}} \right)\)


Discussion

No Comment Found