If f(a) = 2, f'(a) = 1, g(a) = -1, g'(a) = 2 then \(\mathop {\lim }\limits_{x \to a} .\frac{{g(x)f(a) - g(a)f(x)}}{{x - a}}\) is

If f(a) = 2, f'(a) = 1, g(a) = -1, g'(a) = 2 then \(\mathop {\lim }\l

1.	If f(a) = 2, f'(a) = 1, g(a) = -1, g'(a) = 2 then \(\mathop {\lim }\limits_{x \to a} .\frac{{g(x)f(a) - g(a)f(x)}}{{x - a}}\) is
A.	-5
B.	\(\frac{1}{5}\)
C.	5
D.	0
Answer» D. 0

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