If a differentiable function f(x) satisfies \(\mathop {\lim }\limits_{x \to - 1} \dfrac{f(x)+1}{x^2-1}=-\dfrac{3}{2}\) then what is \(\mathop {\lim }\limits_{x \to - 1} f(x)\) equal to?

If a differentiable function f(x) satisfies \(\mathop {\lim }\limits_

1.	If a differentiable function f(x) satisfies \(\mathop {\lim }\limits_{x \to - 1} \dfrac{f(x)+1}{x^2-1}=-\dfrac{3}{2}\) then what is \(\mathop {\lim }\limits_{x \to - 1} f(x)\) equal to?
A.	\(-\dfrac{3}{2}\)
B.	-1
C.	0
D.	1
Answer» C. 0

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If a differentiable function f(x) satisfies \(\mathop {\lim }\limits_{x \to - 1} \dfrac{f(x)+1}{x^2-1}=-\dfrac{3}{2}\) then what is \(\mathop {\lim }\limits_{x \to - 1} f(x)\) equal to?

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