If \(3e^x\ tan\ ydx + (1-e^x)sec^2\ ydy = 0\),then y is

1.	If \(3e^x\ tan\ ydx + (1-e^x)sec^2\ ydy = 0\),then y is
A.	tan y = c(1 + ex)3
B.	y = c(1 - ex)3
C.	log y = c(1 + ex)3
D.	tan y = c(1 - ex)3
Answer» E.

Discussion

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