Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:

Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area o

1.	Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:
A.	\(\frac{8\sqrt3}{5}cm\)
B.	\(\frac{3\sqrt7}{5}cm\)
C.	\(\frac{4\sqrt7}{5}cm\)
D.	\(\frac{7\sqrt3}{5}cm\)
Answer» E.

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Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:

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