Fundamental momentum equation for a hydraulic jump, is – McqOptions

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1.	Fundamental momentum equation for a hydraulic jump, is
A.	D₁² - D₂² = (2q/g) × (V₁ - V₂)
B.	D₂² - D₁² = (2q/g) × (V - V₂)
C.	D₁² - D₂² = (2q/g) × (V₂ - V₁)
D.	D₁² + D₂² = (2q/g) × (V₂ - V₁)
Answer» C. D₁² - D₂² = (2q/g) × (V₂ - V₁)

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