For the Ordinary Differential Equation \(\frac{{{d^2}x}}{{d{t^2}}} - 5\frac{{dx}}{{dt}} + 6x = 0,\) with initial conditions x(0) = 0 and \(\frac{{dx}}{{dt}}\left( 0 \right) = 10,\) the solution is

For the Ordinary Differential Equation \(\frac{{{d^2}x}}{{d{t^2}}} - 5

1.	For the Ordinary Differential Equation \(\frac{{{d^2}x}}{{d{t^2}}} - 5\frac{{dx}}{{dt}} + 6x = 0,\) with initial conditions x(0) = 0 and \(\frac{{dx}}{{dt}}\left( 0 \right) = 10,\) the solution is
A.	-5e2t +6e3t
B.	5e2t = + 6e3t
C.	-10e2t + 10e3t
D.	10e2t + 10e+3t
Answer» D. 10e2t + 10e+3t

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