For a steady flow, the velocity field is \(\vec V = \left( { - {x^2} + – McqOptions

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1.	For a steady flow, the velocity field is \(\vec V = \left( { - {x^2} + 3y} \right)\hat i + \left( {2xy} \right)\hat j\) . The magnitude of the acceleration of a particle at (1, -1) is
A.	2
B.	1
C.	\(2\sqrt 5 \)
D.	0
Answer» D. 0

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