Expand the term $\rho_{i,j}^{t+\Delta t}$ for the MacCormack’s technique.Note:t →Current time-stepav → Average time-step between t and t+Δ t.

Question

TuteeHUB · Accepted Answer

$\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^{av} \Delta t$

TuteeHUB · Answer

$\rho_{i,j}^t+(\frac{\partial\rho}{\partial t})_{i,j}^{av}\Delta t$

TuteeHUB · Answer

$\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^{av} \Delta t$

TuteeHUB · Answer

$\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^t \Delta t$

TuteeHUB · Answer

$\rho_{i,j}^t+(\frac{\partial\rho}{\partial t})_{i,j}^t \Delta t$

1.	Expand the term \(\rho_{i,j}^{t+\Delta t}\) for the MacCormack’s technique.Note:t →Current time-stepav → Average time-step between t and t+Δ t.
A.	\(\rho_{i,j}^t+(\frac{\partial\rho}{\partial t})_{i,j}^{av}\Delta t\)
B.	\(\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^{av} \Delta t\)
C.	\(\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^t \Delta t\)
D.	\(\rho_{i,j}^t+(\frac{\partial\rho}{\partial t})_{i,j}^t \Delta t\)
Answer» B. \(\rho_{i,j}^{av}+(\frac{\partial\rho}{\partial t})_{i,j}^{av} \Delta t\)

Expand the term \(\rho_{i,j}^{t+\Delta t}\) for the MacCormack’s technique.Note:t →Current time-stepav → Average time-step between t and t+Δ t.