MCQOPTIONS
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MCQOPTIONS
| 1. |
Consider the stencil. What is φe according to the second-order upwind scheme?(Note: φ is the flow variable). |
| A. | \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) |
| B. | \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) c) \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) d) \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_ |
| C. | \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) |
| D. | \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) |
| E. | .a) \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) b) \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) c) \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) d) \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) |
| Answer» E. .a) \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) b) \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_w)\) c) \(\phi_e=\phi_P-\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) d) \(\phi_e=\phi_P+\frac{\phi_P-\phi_W}{x_P-x_W}(x_e-x_c)\) | |