1.

Consider a sampled signal y(t) = 5 x 10-6 x(t) where x(t) = 10 cos (8p x 103)t and ts = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is

A. 5 x 10-6 cos (8p x 103)t
B. 5 x 10-5 cos (8p x 103)t
C. 5 x 10-1 cos(8p x 103)t
D. 10 cos(8p x 103)t
Answer» C. 5 x 10-1 cos(8p x 103)t


Discussion

No Comment Found