A thin disc of mass M and radius R has mass per unit area σ(r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is:

A thin disc of mass M and radius R has mass per unit area σ(r) = kr2

1.	A thin disc of mass M and radius R has mass per unit area σ(r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is:
A.	\(\frac{{M{R^2}}}{3}\)
B.	\(\frac{{2M{R^2}}}{3}\)
C.	\(\frac{{M{R^2}}}{6}\)
D.	\(\frac{{M{R^2}}}{2}\)
Answer» C. \(\frac{{M{R^2}}}{6}\)

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A thin disc of mass M and radius R has mass per unit area σ(r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is:

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