A straight line ‘L’ at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of 60° with the line x + y = 0. Then an equation of the line ‘L’ is:

\(\left( {\sqrt 3 + 1} \right)x + \left( {\sqrt 3 - 1} \right)y = 8\sqrt 2\)

\(\left( {\sqrt 3 - 1} \right)x + \left( {\sqrt 3 + 1} \right)y = 8\sqrt 2\)

A straight line ‘L’ at a distance of 4 units from the origin makes

1.	A straight line ‘L’ at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of 60° with the line x + y = 0. Then an equation of the line ‘L’ is:
A.	\(x + \sqrt 3 y = 8\)
B.	\(\left( {\sqrt 3 + 1} \right)x + \left( {\sqrt 3 - 1} \right)y = 8\sqrt 2\)
C.	\(\sqrt 3 x + y = 8\)
D.	\(\left( {\sqrt 3 - 1} \right)x + \left( {\sqrt 3 + 1} \right)y = 8\sqrt 2\)
Answer» C. \(\sqrt 3 x + y = 8\)

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A straight line ‘L’ at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of 60° with the line x + y = 0. Then an equation of the line ‘L’ is:

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