A quiescent linear time-invariant system subjected to a unit step input u(t) has the response c(t) = te-t, t ≥ 0. Then $\frac{{C\left( s \right)}}{{R\left( s \right)}}$ would be

Question

A quiescent linear time-invariant system subjected to a unit step input u(t) has the response c(t) = te-t, t ≥ 0. Then $\frac{{C\left( s \right)}}{{R\left( s \right)}}$ would be

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{1}{{s\left( {s + 1} \right)}}$

TuteeHUB · Answer

$\frac{1}{{s + 1}}$

TuteeHUB · Answer

$\frac{1}{{{{\left( {s + 1} \right)}^2}}}$

TuteeHUB · Answer

None of the above

1.	A quiescent linear time-invariant system subjected to a unit step input u(t) has the response c(t) = te-t, t ≥ 0. Then \(\frac{{C\left( s \right)}}{{R\left( s \right)}}\) would be
A.	\(\frac{1}{{s\left( {s + 1} \right)}}\)
B.	\(\frac{1}{{s + 1}}\)
C.	\(\frac{1}{{{{\left( {s + 1} \right)}^2}}}\)
D.	None of the above
Answer» E.

A quiescent linear time-invariant system subjected to a unit step input u(t) has the response c(t) = te-t, t ≥ 0. Then \(\frac{{C\left( s \right)}}{{R\left( s \right)}}\) would be

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