MCQOPTIONS
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| 1. |
A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential energy (PE) equals kinetic energy (KE), the position of the particle will be: |
| A. | \(\frac{{\rm{A}}}{2}\) |
| B. | \(\frac{{\rm{A}}}{{2\sqrt 2 }}\) |
| C. | \(\frac{{\rm{A}}}{{\sqrt 2 }}\) |
| D. | A |
| Answer» D. A | |