A first order differential is given by \(\frac{{dy}}{{dx}} = {e^{ - 3x}}\) Find the possible solution out of the following assuming K as constant.

\(- \frac{1}{3}{e^{ - 3x}} + K\)

A first order differential is given by \(\frac{{dy}}{{dx}} = {e^{ - 3x

1.	A first order differential is given by \(\frac{{dy}}{{dx}} = {e^{ - 3x}}\) Find the possible solution out of the following assuming K as constant.
A.	e3x + K
B.	\(- \frac{1}{3}{e^{ - 3x}} + K\)
C.	\(- \frac{1}{3}{e^{3x}} + K\)
D.	-3e3x + K
Answer» C. \(- \frac{1}{3}{e^{3x}} + K\)

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