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This section includes 194 Mcqs, each offering curated multiple-choice questions to sharpen your Strength Materials knowledge and support exam preparation. Choose a topic below to get started.
101. |
A uniformly distributed load w (kN/m) is acting over the entire length of 8 m long cantilever beam. If the shear force at the midpoint of cantilever beam is 12 kN. What is the value of w? |
A. | 6 |
B. | 4 |
C. | 5 |
D. | 3 |
Answer» E. | |
102. |
In beam where shear force changes its sign, the bending moment will be |
A. | minimum |
B. | zero |
C. | maximum |
D. | same as shear force |
Answer» D. same as shear force | |
103. |
In a simply supported beam, where the shear force is zero, the bending moment will be _______. |
A. | Zero |
B. | Maximum |
C. | Minimum |
D. | Zero or minimum |
Answer» C. Minimum | |
104. |
A simply supported beam carries a load ‘P’ through a bracket as shown in figure. The maximum bending moment in the beam is |
A. | \(P\frac{l}{2}\) |
B. | \(P\frac{l}{2}+\frac{a\cdot P}{2}\) |
C. | \(\frac{Pl}{4}+\frac{Pa}{2}\) |
D. | \(P\frac{l}{2}-a\cdot P\) |
Answer» D. \(P\frac{l}{2}-a\cdot P\) | |
105. |
A cantilever 9 m long has uniformly distributed load over the entire length. The maximum bending moment is 8100 N-m, the rate of loading is: |
A. | 200 N/m |
B. | 100 N/m |
C. | 400 N/m |
D. | 900 N/m |
Answer» B. 100 N/m | |
106. |
For a particular load distribution and support conditions in a beam of length L, bending moment at any section x(0 < x < L) is given by M(x) = Ax – Bx2, where A and B are constants. The shear force in the beam will be zero at |
A. | \(x = \frac{A}{{2B}}\) |
B. | \(x = \frac{A}{B}\) |
C. | \(x = \frac{{2A}}{B}\) |
D. | x = L |
Answer» B. \(x = \frac{A}{B}\) | |
107. |
Maximum shear stress in a beam of rectangular cross section is ________ times the average shear stress. |
A. | 1.25 |
B. | 1.5 |
C. | 2.0 |
D. | 4.0 |
Answer» C. 2.0 | |
108. |
In the adjacent bam, the point of contra flexure is at a distance of |
A. | 2.4 m towards right of B |
B. | At B |
C. | At C |
D. | At 2.4 m from A |
E. | At the midpoint of AD |
Answer» E. At the midpoint of AD | |
109. |
A beam is having a triangular cross-section with its neutral axis XX. The section modulus about XX is given by |
A. | bh2/6 |
B. | bh2/36 |
C. | bh2/24 |
D. | hb2/36 |
Answer» D. hb2/36 | |
110. |
In a simply supported beam carrying a uniformly distributed load ‘w’ per unit length, the point of contraflexure |
A. | Lies in the centre of the beam |
B. | Lies at the ends of the beam |
C. | Depends upon the length of the beam |
D. | Does not exist |
Answer» E. | |
111. |
A simply supported beam of span (l) carries a point load (W) at the centre of the beam. The bending moment diagram will be |
A. | parabola with maximum ordinate at the centre of the beam |
B. | parabola with maximum ordinate at one end of the beam |
C. | triangle with maximum ordinate at the centre of the beam |
D. | triangle with maximum ordinate at one end of the beam |
Answer» D. triangle with maximum ordinate at one end of the beam | |
112. |
In the figure given below, the beam will be stable only if - |
A. | x = √2y |
B. | x = 2y |
C. | √2x = y |
D. | 2x = y |
Answer» D. 2x = y | |
113. |
A cantilever of length (l) carries a uniformly distributed load over the whole length. The shear force diagram will be |
A. | Two equal and opposite rectangles |
B. | A rectangle |
C. | Two equal and opposite triangles |
D. | A triangle |
Answer» E. | |
114. |
In the adjacent beam, the maximum shear force is |
A. | ax |
B. | 2ax |
C. | ax/2 |
D. | ax/4 |
E. | 4ax |
Answer» B. 2ax | |
115. |
Consider the following statements :If at section away from the ends of the beam, M represents the bending moment, V the shear force, w the intensity of loading and y represents the deflection of the beam at the section, then1. \(\frac{{dM}}{{dx}} = V\)2. \(\frac{{dV}}{{dx}} = w\)3. \(\frac{{dw}}{{dx}} = y\)Of these statements: |
A. | 1 and 2 are correct |
B. | 1 and 3 are correct |
C. | 2 and 3 are correct |
D. | 1, 2 and 3 are correct |
Answer» B. 1 and 3 are correct | |
116. |
Consider the three prismatic beams with the clamped supports, P, Q and R as shown in the figures.Given that the modulus of elasticity. E is 2.5 × 104 MPa and the moment of inertia I is 8 × 108 mm4, the correct comparison of the magnitudes of the shear force S and the bending moment M developed at the supports is |
A. | SP < SQ < SR, MP = MQ = MR |
B. | SP = SQ > SR, MP = MQ > MR |
C. | SP < SQ > SR, MP = MQ = MR |
D. | SP < SQ < SR, MP = MQ < MR |
Answer» D. SP < SQ < SR, MP = MQ < MR | |
117. |
If a simply supported beam is loaded with point load W at the centre then what is the ratio of bending moment at the support to the bending moment at the centre? |
A. | 0.5 |
B. | 0 |
C. | 1 |
D. | 2 |
Answer» C. 1 | |
118. |
A simply supported beam of length L is subjected to a varying distributed load sin (πx/L) N/m, where distance x is measured from the left support. The magnitude of the vertical reaction in N at the left support is |
A. | 3L/π |
B. | 2L/π |
C. | L/2π |
D. | L/π |
Answer» E. | |
119. |
In a fixed beam having a uniformly distributed load over the whole span, the moments will be calculated by the formula- |
A. | wL2 / 12 |
B. | wL3 / 8 |
C. | wL2 / 8 |
D. | wL3 / 12 |
Answer» B. wL3 / 8 | |
120. |
In a simply supported beam of 10 m span having udl of 8 kN/m, the maximum Bending Moment shall be |
A. | 80 kNm |
B. | 100 kNm |
C. | 0.8 kNm |
D. | 10 kNm |
Answer» C. 0.8 kNm | |
121. |
A simply supported beam of span L is subjected to a moment M0 at a distance of \(\frac{L}{4}\) from the left end. Magnitude of the maximum bending moment in the beam is |
A. | M0 |
B. | \(\frac{{{M_o}}}{2}\) |
C. | \(\frac{{{M_o}}}{4}\) |
D. | \(\frac{{3{M_o}}}{4}\) |
Answer» E. | |
122. |
A simply supported beam PQ is loaded by a moment of 1 kN-m at the mid span of the beam of length 1 m. The reaction forces RP and RQ at supports P and Q respectively are |
A. | 1 kN downward, 1 kN upward |
B. | 0.5 kN upward, 0.5 kN downward |
C. | 0.5 kN downward, 1 kN upward |
D. | 0.5 kN upward, 0.5 kN upward |
Answer» B. 0.5 kN upward, 0.5 kN downward | |
123. |
The bending moment diagram for an ‹overhanging beam is shown in the figure. The points of contra flexure would include |
A. | A and F |
B. | B and E |
C. | C and D |
D. | A and D |
Answer» D. A and D | |
124. |
A simply supported beam of length L is subjected to a varying distributed load \(\sin \left( {3\pi \frac{x}{L}} \right)N{m^{ - 1}}\), where the distance x is measured from the left support. The magnitude of the vertical force in N at the left support is |
A. | zero |
B. | L/3π |
C. | L/π |
D. | 2L/π |
Answer» C. L/π | |
125. |
A simply supported prismatic beam of span, L and section modulus, Z has an overhang of 0.4L is loaded with uniformly distributed load, q throughout the span. The maximum bending stress induced is: |
A. | \(\pm 0.02\frac{{q{L^2}}}{Z}\) |
B. | \(\pm 0.04\frac{{q{L^2}}}{Z}\) |
C. | \(\pm 0.08\frac{{q{L^2}}}{Z}\) |
D. | \(\pm \;0.085\frac{{q{L^2}}}{Z}\) |
Answer» E. | |
126. |
A simply supported beam has equal overhanging lengths and carries equal concentrated loads P at ends, bending moment over the length between the supports |
A. | is zero |
B. | is non-zero constant |
C. | varies uniformly from one support to the other |
D. | is maximum at mid span |
Answer» C. varies uniformly from one support to the other | |
127. |
Area moment of inertia of the cross-section of the beam resist |
A. | The applied normal force |
B. | Both the torque and bending moment |
C. | The applied torque |
D. | The applied bending moment of the beam |
Answer» E. | |
128. |
A uniformly distributed load w (in kN/m) is action over the entire length of a 3 m long cantilever beam. If the shear force at the mid-point of cantilever is 6 kN, what is the value of w? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» D. 5 | |
129. |
A cantilever and a simply supported beam have the same length and are subject to the same uniformly distributed load. The ratio of their maximum bending moments is |
A. | 1 |
B. | 3 |
C. | 4 |
D. | 2 |
Answer» D. 2 | |
130. |
A propped cantilever beam of span L is subjected to Uniformly Distributed Load of W kN/m throughout the span. What is the distance of the Point of Contraflexure from the Fixed end? |
A. | 0.175 L |
B. | 0.25 L |
C. | 0.33 L |
D. | 0.375 L |
Answer» C. 0.33 L | |
131. |
A continuous beam ABC is simply supported at supports A, B and C. Portion AB has span of 6 m and BC 4 m. Portion AB is loaded with a concentrated load of 120 kN downward at 3 m from A. The qualitative reactions shall be |
A. | Reactions at A and B shall be upward and reaction at C shall be zero |
B. | Reactions at A and B shall be upward and reaction at C shall be downward |
C. | All reactions i.e., at A, B and C shall be upwards |
D. | None of the above |
Answer» C. All reactions i.e., at A, B and C shall be upwards | |
132. |
A cantilever beam of span L is subjected to uniformly varying load having value of w kN/m at the free end and 0 kN/m at the fixed end. The magnitude of slope of shear force diagram at the fixed end is _________ the magnitude of the slope of shear force diagram at the free end |
A. | same as |
B. | less than |
C. | w times more than |
D. | wL/2 times more than |
Answer» C. w times more than | |
133. |
What is variation in SFD, if the type of loading in the simply supported beam is U.D.L is ____ |
A. | Rectangle |
B. | Linear |
C. | Trapezoidal |
D. | Parabolic |
Answer» C. Trapezoidal | |
134. |
At hinge, the moments will be _________ |
A. | Maximum |
B. | Minimum |
C. | Uniform |
D. | Zero |
Answer» E. | |
135. |
What is the variation in the BM, if the simply supported beam carries a point load at the centre. |
A. | Triangular |
B. | Rectangular |
C. | Trapezoidal |
D. | Other quadrilateral |
Answer» B. Rectangular | |
136. |
The shear force in a beam subjected to pure positive bending is _____ |
A. | Positive |
B. | Negative |
C. | Zero |
D. | Cannot determine |
Answer» D. Cannot determine | |
137. |
Maximum bending moment in a cantilever beam subjected to udl (w)over the entire span (l). |
A. | wl |
B. | wl³ |
C. | wl² |
D. | w |
Answer» D. w | |
138. |
The rate of change of shear force is equal to _____ |
A. | Direction of load |
B. | Change in BMD |
C. | Intensity of loading |
D. | Maximum bending |
Answer» D. Maximum bending | |
139. |
Number of points of contra flexure for a double over hanging beam. |
A. | 3 |
B. | 2 |
C. | 4 |
D. | Infinite |
Answer» C. 4 | |
140. |
For a simply supported beam, the moment at the support is always __________ |
A. | Maximum |
B. | Zero |
C. | Minimum |
D. | Cannot be determined |
Answer» C. Minimum | |
141. |
“Hinged support offers resistance against rotation”. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
142. |
Roller support is same as _____ |
A. | Hinged support |
B. | Fixed support |
C. | Simply support |
D. | Roller support |
Answer» D. Roller support | |
143. |
When SF is zero, the bending moment is _____ |
A. | Zero |
B. | Maximum |
C. | Very difficult to say |
D. | Minimum |
Answer» B. Maximum | |
144. |
What is the maximum bending moment for simply supported beam carrying a point load “W” kN at its centre? |
A. | W kNm |
B. | W/m kNm |
C. | W×l kNm |
D. | W×l/4 kNm |
Answer» E. | |
145. |
A cantilever beam subjected to point load at its free end, the maximum bending moment develops at the ________ of the beam. |
A. | Free end |
B. | Fixed end |
C. | Centre |
D. | Point of inflection |
Answer» C. Centre | |
146. |
A cantilever beam loaded with udl throughout, the maximum shear force occurs at____ |
A. | Free end |
B. | Fixed end |
C. | At centre |
D. | At point of contraflexure |
Answer» C. At centre | |
147. |
A simply supported beam of span 1 m carries a point load “w” in centre determine the shear force in the half left of the beam. |
A. | W/3 |
B. | W/4 |
C. | W/2 |
D. | W |
Answer» D. W | |
148. |
Point of inflection is known as _____ |
A. | Point of regurrence |
B. | Point of contraflexure |
C. | Point of rigid factor |
D. | Point of flexural moment |
Answer» C. Point of rigid factor | |
149. |
The relation between slope and maximum bending moment is _________ |
A. | Directly proportion |
B. | Inversely proportion |
C. | Relative proportion |
D. | Mutual incidence |
Answer» C. Relative proportion | |
150. |
In SFD, vertical lines are for ______ |
A. | Point loads |
B. | UDL |
C. | UVL |
D. | LDP |
Answer» B. UDL | |